The Moho as G0/G1 Register Boundary

R = 20,000/π km · Seismic Velocities as Pure {2,3} Lattice · Sidereal Year = Moho Year × 730/729

Stephen Daubney · The Daubney Foundation

P-MOHO-1 to P-MOHO-6 R = 20,000/π km Vp = 2³ km/s Vs = 3²/2 km/s 730/729 year identity Earth Sciences

P-MOHO-1 · The Moho as a Tau-Register Transition

The Moho discontinuity marks the G0/G1 Tau-register boundary in Earth's interior. Below it: the dense G0 mantle/core lattice. Above it: the open G1 crust, ocean, and atmosphere. The seismic velocity jump at the Moho is the direct observational signature of this register transition.

P-MOHO-1
The Moho discontinuity is the G0/G1 Tau-register boundary. Below: dense Tau-lattice (mantle/core). Above: open Tau-lattice (crust/ocean/atmosphere). The seismic velocity discontinuity is the register transition signature.

P-MOHO-2 · Earth Radius = 20,000/π km

The FOT Tau-lattice assigns Earth a canonical radius of exactly 20,000/π kilometres — the radius of a sphere whose circumference is precisely 40,000 km. This is the value encoded into the SI metre by the 1791 French Académie definition.

R_Earth (FOT) = 20,000 / π = 6,366.1977… km Circumference (FOT) = 2π × R = 40,000.000 km (exact) 40,000 = 2⁷ × 5⁴ (pure {2,5} lattice) Conventional mean radius = 6,371.0 km (753 ppm Radian Veil)

P-MOHO-3 · Seismic Velocities as Pure {2,3} Values

At the Moho, compressional and shear wave velocities fall on the {2,3} sub-lattice of the FOT prime lattice. Observed centre values lie within 220 ppm of the exact lattice values — within the canonical Radian Veil band.

Vp (Moho) = 2³ = 8.000 km/s Vs (Moho) = 3² / 2 = 4.500 km/s Vp / Vs = 16/9 = (4/3)² — perfect fourth squared
Wave typeFOT exact (km/s)Observed range (km/s)Centre PPM
P-wave (Vp)8.0007.6 – 8.1~60 ppm
S-wave (Vs)4.5004.0 – 4.7~220 ppm
Ratio Vp/Vs1.7778 (16/9)1.72 – 1.78within band

P-MOHO-4 · Vp/Vs = 16/9 as a Tau-Lattice Fraction

The ratio 16/9 = (4/3)² is a fundamental Tau-lattice fraction — the square of the perfect fourth musical interval. It recurs across acoustic, harmonic, and molecular domains, confirming it as a primary Tau-coupling constant.

P-MOHO-5 · Sidereal Year = Moho Year × 730/729

The FOT derivation of the sidereal year proceeds through the Moho orbital period — the characteristic oscillation time of the G0/G1 register boundary. The correction factor 730/729 = (3⁶ + 1)/3⁶ introduces the sixth power of prime 3.

T_sidereal = T_Moho × 730/729 T_Moho = (3600 / π²) × (3⁶ + 1) / 3⁶ [days] T_sidereal (FOT) = 365.25661 days T_sidereal (IAU) = 365.25636 days (0.692 ppm)

P-MOHO-6 · The 1/(5π) Equalisation Factor

The factor 1/(5π) is the coupling constant at the G0/G1 register boundary — the only {2,3,5,π} value that equates the orbital Tau-wave period with the radial seismic wave period at R = 20,000/π km.

Coupling constant = 1 / (5π) T_orbital / T_seismic = 5π at the Moho surface 5π = 15.70796… (prime 5 × sphere constant π)
The 1/(5π) coupling is not derived from gravity, pressure, or composition. It is a pure geometric requirement of the Tau-field — the same 5π that appears in quantum mechanics and orbital lattice formulas. Scale invariance is the mechanism, not a metaphor.

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